2-0.25x^2-x=0

Solution for 2-0.25x^2-x=0 equation:

2-0.25x^2-x=0

We add all the numbers together, and all the variables

-0.25x^2-1x+2=0

a = -0.25; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·(-0.25)·2
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3}}{2*-0.25}=\frac{1-\sqrt{3}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3}}{2*-0.25}=\frac{1+\sqrt{3}}{-0.5}
$